Flutter直接调用原生页面,并接收返回参数

Posted by アライさん on 2019年10月22日

可参考 “Flutter 创建plugin package插件” 条目

  • flutter 部分
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import 'package:flutter/services.dart';
//通道名称为samples.flutter.io/battery,和android原生中接收的一样
static const platform = const MethodChannel('samples.alois.test_channel');
String result = await platform.invokeMethod('action1',['arg0',2]);
  • flutter android原生部分
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class MainActivity : FlutterActivity() {
//通道名称为samples.flutter.io/battery,和flutter中的一样
private val channelName = "samples.alois.test_channel"

private val customRequestCode = 1032
private var myResult: MethodChannel.Result? = null

override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {//API>21,设置状态栏颜色透明
window.statusBarColor = 0
}
GeneratedPluginRegistrant.registerWith(this)
//通过通道监听对应名字的方法
MethodChannel(flutterView, channelName).setMethodCallHandler { methodCall, result ->
myResult = result
if (methodCall.method == "action1") {
try {
val args = methodCall.arguments<Any>() as List<Any>
startActivity(args[0] as String, args[1] as Int)
} catch (e: Exception) {
}

} else {
result.notImplemented()
}
}

}

// 打开activity
private fun startActivity( arg0:String, arg1:Int) {
val intent = Intent(this, TempActivity::class.java)
intent.putExtra("startKey0",arg0)
intent.putExtra("startKey1", arg1)
this.startActivityForResult(intent, customRequestCode)
}

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)

if (requestCode == customRequestCode && resultCode == Activity.RESULT_OK) {
val value = data?.getStringExtra("finishKey") ?: ""
myResult?.success(value)
}
}
}